-4y^2+32y=104

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Solution for -4y^2+32y=104 equation: 



-4y^2+32y=104

We move all terms to the left:

-4y^2+32y-(104)=0

a = -4; b = 32; c = -104;
Δ = b2-4ac
Δ = 322-4·(-4)·(-104)
Δ = -640
Delta is less than zero, so there is no solution for the equation

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